



1, 3, 4, 5, 6, 8, 10, 12, 14, 15, 16, 17, 19, 20, 21, 22, 24, 25, 26, 27, 29, 30, 31, 32, 34, 36, 38, 40, 41, 42, 43, 45, 47, 49, 51, 52, 53, 54, 56, 58, 60, 62, 63, 64, 65, 67, 69, 71, 73, 74, 75, 76, 78, 79, 80, 81, 83, 84, 85, 86, 88, 89, 90, 91, 93, 95
(list;
graph;
refs;
listen;
history;
text;
internal format)



OFFSET

1,2


COMMENTS

Conjecture: a(n)/n > (5+sqrt(13))/6.
From Andrey Zabolotskiy, Apr 13 2017: The conjecture is true since it states that the fraction of 0's is equal 6/(5+sqrt(13)), which is the invariant value of fraction of 0's under the morphism.


LINKS

Clark Kimberling, Table of n, a(n) for n = 1..10000


EXAMPLE

As a word, A284745 = 01000010101..., in which 0 is in positions 1,3,4,5,6,8,...


MATHEMATICA

s = Nest[Flatten[# /. {0 > {0, 1}, 1 > {0, 0, 0}}] &, {0}, 7] (* A284745 *)
Flatten[Position[s, 0]] (* A191263 *)
Flatten[Position[s, 1]] (* A284746 *)


CROSSREFS

Cf. A191263, A284744.
Sequence in context: A136497 A055563 A090161 * A121540 A026512 A026506
Adjacent sequences: A284743 A284744 A284745 * A284747 A284748 A284749


KEYWORD

nonn,easy


AUTHOR

Clark Kimberling, Apr 13 2017


STATUS

approved



