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A284604
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Quadratic recurrence: a(n+2) = a(n+1)^2 + a(n)^2 + 1, with a(0) = a(1) = 1.
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0
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OFFSET
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0,3
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LINKS
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FORMULA
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a(n+3) = a(n+2)^2 + a(n+2) - a(n)^2, with a(0) = a(1) = 1, a(2) = 3.
a(n) ~ c^(2^n), where c = 1.356519333072951374233963037913978335267300244021120535099185060013... - Vaclav Kotesovec, Apr 15 2017
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MATHEMATICA
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RecurrenceTable[{a[n + 2] == a[n + 1]^2 + a[n]^2 + 1, a[0] == 1, a[1] == 1}, a, {n, 0, 12}]
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PROG
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(Maxima) a(n) := if (n=0 or n=1) then 1 else a(n-1)^2 + a(n-2)^2 + 1; makelist(a(n), n, 0, 12);
(Magma) [n le 2 select 1 else Self(n-1)^2+Self(n-2)^2+1: n in [1..10]]; // Bruno Berselli, Mar 30 2017
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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