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A283811
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Poly-Bernoulli numbers B_n^(k) with k = -5.
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3
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1, 32, 454, 4718, 41506, 329462, 2441314, 17234438, 117437746, 779305142, 5067707074, 32440729958, 205120773586, 1284333040022, 7978977787234, 49258610238278, 302555048903026, 1850666770922102, 11281963755617794, 68586728901231398, 416015651355490066
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OFFSET
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0,2
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COMMENTS
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a(n) is also the number of acyclic orientations of the complete bipartite graph K_{5,n}. - Vincent Pilaud, Sep 16 2020
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LINKS
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FORMULA
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a(n) = 120*6^n - 240*5^n + 150*4^n - 30*3^n + 2^n.
G.f.: (1 - x)*(1 + 13*x - 18*x^2) / ((1 - 2*x)*(1 - 3*x)*(1 - 4*x)*(1 - 5*x)*(1 - 6*x)).
a(n) = 20*a(n-1) - 155*a(n-2) + 580*a(n-3) - 1044*a(n-4) + 720*a(n-5) for n>4.
(End)
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MATHEMATICA
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Table[120*6^n - 240*5^n + 150*4^n - 30*3^n + 2^n , {n, 0, 20}] (* Indranil Ghosh, Mar 17 2017 *)
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PROG
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(PARI) a(n) = 120*6^n - 240*5^n + 150*4^n - 30*3^n + 2^n; \\ Indranil Ghosh, Mar 17 2017
(PARI) Vec((1 - x)*(1 + 13*x - 18*x^2) / ((1 - 2*x)*(1 - 3*x)*(1 - 4*x)*(1 - 5*x)*(1 - 6*x)) + O(x^25)) \\ Colin Barker, Oct 14 2020
(Python) def A283811(n): return 120*6**n - 240*5**n + 150*4**n - 30*3**n + 2**n # Indranil Ghosh, Mar 17 2017
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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