login

Year-end appeal: Please make a donation to the OEIS Foundation to support ongoing development and maintenance of the OEIS. We are now in our 61st year, we have over 378,000 sequences, and we’ve reached 11,000 citations (which often say “discovered thanks to the OEIS”).

A281300
Triangular array read by rows: T(n, k) = (((binomial(2*p-1, p-1)-1)/p^3) mod q) + (((binomial(2*q-1, q-1)-1)/q^3) mod p), where p = prime(n) and q = prime(k) for k = 1..n-1.
0
2, 5, 3, 3, 7, 1, 4, 5, 1, 11, 11, 9, 3, 6, 7, 14, 7, 4, 9, 13, 13, 6, 15, 2, 6, 27, 11, 19, 7, 9, 3, 8, 17, 22, 34, 27, 23, 11, 2, 11, 9, 25, 15, 38, 17, 9, 21, 4, 6, 24, 16, 14, 28, 4, 30, 29, 25, 1, 11, 14, 41, 38, 30, 44, 27, 13, 32, 15, 5, 6, 28, 39, 30
OFFSET
1,1
COMMENTS
Is p*q always a term of A228562 for T(n, k) = 0?
Is every term t of A228562 a term of A006881 with T(x, y) = 0, where x and y are the indices of the two prime factors of t in A000040?
FORMULA
T(n, k) = A034602(n) % prime(k) + A034602(k) % prime(n).
EXAMPLE
Triangle starts
2
5, 3
3, 7, 1
4, 5, 1, 11
11, 9, 3, 6, 7
14, 7, 4, 9, 13, 13
6, 15, 2, 6, 27, 11, 19
7, 9, 3, 8, 17, 22, 34, 27
PROG
(PARI) t(n, k) = my(p=prime(n), q=prime(k)); lift(Mod((binomial(2*q-1, q-1)-1)/q^3, p)) + lift(Mod((binomial(2*p-1, p-1)-1)/p^3, q))
trianglerows(n) = for(x=2, n+1, for(y=1, x-1, print1(t(x, y), ", ")); print(""))
trianglerows(8) \\ print initial 8 rows of triangle
CROSSREFS
Sequence in context: A141637 A185581 A151960 * A115320 A378911 A073480
KEYWORD
nonn,tabl
AUTHOR
Felix Fröhlich, Jan 19 2017
STATUS
approved