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 A278066 Relative of Hofstadter Q-sequence: a(1) = 5, a(2) = 2; thereafter a(n) = a(n-a(n-1)) + a(n-a(n-2)). 14
 5, 2, 5, 2, 5, 7, 2, 12, 2, 12, 2, 12, 7, 4, 14, 14, 10, 14, 7, 14, 6, 26, 10, 4, 20, 33, 2, 33, 2, 33, 2, 33, 2, 38, 2, 38, 2, 38, 7, 4, 40, 40, 10, 40, 7, 14, 6, 78, 10, 4, 46, 85, 2, 85, 2, 85, 2, 85, 2, 85, 2, 85, 2, 85, 2, 85, 2, 85, 2, 85, 2, 85, 2, 85, 2, 85, 2 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,1 COMMENTS In calculating terms of this sequence, use the convention that a(n)=0 for n<=0. Most terms in this sequence alternate between 2 and a term of A275163. These runs are separated by 18 other terms, and each run is approximately twice as long as the previous. LINKS Nathan Fox, Table of n, a(n) for n = 1..10000 N. Fox, Hofstadter-like Sequences over Nonstandard Integers", Talk given at the Rutgers Experimental Mathematics Seminar, November 10 2016. FORMULA a(1) = 5, a(2) = 2, a(3) = 5, a(4) = 2, a(5) = 5, a(6) = 7, a(7) = 2; thereafter, for k>=0, a(A275163(k)+1)=A275163(k)+5 a(A275163(k)+2)=2 a(A275163(k)+3)=A275163(k)+5 a(A275163(k)+4)=2 a(A275163(k)+5)=A275163(k)+5 a(A275163(k)+6)=7 a(A275163(k)+7)=4 a(A275163(k)+8)=A275163(k)+7 a(A275163(k)+9)=A275163(k)+7 a(A275163(k)+10)=10 a(A275163(k)+11)=A275163(k)+7 a(A275163(k)+12)=7 a(A275163(k)+13)=14 a(A275163(k)+14)=6 a(A275163(k)+15)=2*A275163(k)+12 a(A275163(k)+16)=10 a(A275163(k)+17)=4 a(A275163(k)+18)=A275163(k)+13 a(A275163(k)+i)=A275163(k+1), i odd, 19<=i

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Last modified June 17 17:01 EDT 2021. Contains 345085 sequences. (Running on oeis4.)