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%I #6 Sep 08 2016 17:52:52
%S 0,1,3,2,5,4,8,7,6,11,10,9,14,13,12,18,17,16,15,23,22,21,20,19,28,27,
%T 26,25,24,34,33,32,31,30,29,40,39,38,37,36,35,47,46,45,44,43,42,41,54,
%U 53,52,51,50,49,48,61,60,59,58,57,56,55,69,68,67,66,65,64,63,62,77,76,75,74,73,72,71,70,86,85,84,83,82,81,80,79,78
%N Simple self-inverse permutation of natural numbers: after a(0)=0, list each block of A261224(n) numbers in reverse order, from A261222(n) to A261223(1+n).
%C Maps between A276583 and A276584.
%H Antti Karttunen, <a href="/A276582/b276582.txt">Table of n, a(n) for n = 0..9996</a>
%H <a href="/index/Per#IntegerPermutation">Index entries for sequences that are permutations of the natural numbers</a>
%F a(0)=0; for n >= 1, a(n) = (A261223(1+A276581(n))- n)+A261222(A276581(n)).
%o (Scheme)
%o (define (A276582 n) (if (zero? n) n (+ (- (A261223 (+ 1 (A276581 n))) n) (A261222 (A276581 n)))))
%Y Cf. A261222, A261223, A261224, A276581, A276583, A276584.
%K nonn
%O 0,3
%A _Antti Karttunen_, Sep 07 2016
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