OFFSET
1,1
COMMENTS
Let U = {F(i)F(j), 2 < i < j}, where F = A000045 (Fibonacci numbers), and V = {L(i)L(j), 0 < i < j}, where L = A000032 (Lucas numbers). The sets U and V are disjoint, and their union, arranged as a sequence in increasing order, is A274429. (Unlike A274426, here all the Lucas numbers except 1 are included.)
Writing u for a Fibonacci product and v for a Lucas product, the numbers in A274429 are represented by the infinite word vvuvuvvuuvvuuvvvuuuvvvuuuvvvv... This is the concatenation of v and the words (v^k)(u^k)(v^k)(u^k) for k >= 1. Thus, there are runs of Fibonacci products of every finite length and runs of Lucas products of every finite length.
See A274426 for a guide to related sequences.
MATHEMATICA
z = 200; f[n_] := Fibonacci[n];
u = Take[Sort[Flatten[Table[f[m] f[n], {n, 3, z}, {m, 3, n - 1}]]], 100]
g[n_] := LucasL[n];
v = Take[Sort[Flatten[Table[g[u] g[v], {u, 1, z}, {v, 1, u - 1}]]], z]
Intersection[u, v]
w = Union[u, v] (* A274429 *)
Select[Range[300], MemberQ[u, w[[#]]] &] (* A274430 *)
Select[Range[300], MemberQ[v, w[[#]]] &] (* A274431 *)
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Clark Kimberling, Jun 22 2016
STATUS
approved