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A273555
a(n) = A001235(n) - floor(A001235(n)^(1/3))^3.
1
1, 8, 8, 1000, 64, 8, 729, 27, 232, 1728, 64, 216, 1728, 512, 8000, 4913, 729, 27, 125, 512, 64, 5832, 13331, 216, 13580, 125, 4913, 1000, 1856, 3375, 13824, 7073, 343, 2547, 8, 1331, 12167, 512, 1728, 8000, 13824, 13768, 24389, 9736, 16496, 216, 12167, 13824, 19683, 1
OFFSET
1,2
COMMENTS
Noncube terms of this sequence are 232, 13331, 13580, 1856, 7073, 2547, ...
How is the distribution of noncube terms in this sequence? See also A273592 that is related with this question.
FORMULA
a(n) = A055400(A001235(n)). - Michel Marcus, May 25 2016
PROG
(PARI) T = thueinit(x^3+1, 1);
isA001235(n) = my(v=thue(T, n)); sum(i=1, #v, v[i][1]>=0 && v[i][2]>=v[i][1])>1;
lista(nn) = for(n=1, nn, if(isA001235(n), print1(n-sqrtnint(n, 3)^3, ", ")));
CROSSREFS
KEYWORD
nonn
AUTHOR
Altug Alkan, May 25 2016
STATUS
approved