A272884 Squares whose digits are powers of 2.

1, 4, 81, 121, 144, 441, 484, 841, 1444, 8281, 11881, 14884, 28224, 48841, 114244, 128881, 142884, 221841, 228484, 848241, 1121481, 1281424, 1418481, 2184484, 2214144, 8282884, 11142244, 11282881, 18241441, 18818244, 18844281, 21242881, 21818241, 28281124, 82428241, 121242121, 121484484, 124121881

Offset

1,2

Comments

Intersection of A000290 and A028846.

Note that in contrast to this sequence, which contains 102 terms up to 10^12, the analogous sequence of cubes (A272826) may contain only 3 in total.

Moreover, the similar sequences for the fourth and fifth perfect powers seem to contain only two terms (1, 81) in the case of the former and only one term (1) in the case of the latter. Higher powers also appear to produce sequences with one (mostly) or two terms only.

Unlike the analogous sequence for cubes, this sequence is heuristically infinite. - Charles R Greathouse IV, May 08 2016

This sequence is infinite because it contains the squares of the numbers of the forms 10*(10^k-1)/3+8 and 100*(10^k-1)/3+59. - Giovanni Resta, May 09 2016

Additionally, this sequence contains the squares of the numbers of the form 1000*(10^k-1)/3 + 809 for k > 2. For k > 2, numbers of the form (1000*(10^k-1)/3 + 809)^2 contains all digits that are powers of 2. - Altug Alkan, May 14 2016

Links

Giovanni Resta, Table of n, a(n) for n = 1..10000

Example

144 is a term as its digits are only powers of 2 and it is a square, 144 = 12^2.

Mathematica

Select[Range[12000]^2, SubsetQ[{1, 2, 4, 8}, IntegerDigits@#] &]

Prog

(PARI) is(n)=issquare(n) && #setintersect(Set(digits(n)), [0, 3, 5, 6, 7, 9])==0 \\ Charles R Greathouse IV, May 08 2016

Crossrefs

Cf. A000290 (squares), A028846 (numbers whose digits are powers of 2), A272826 (similar sequence for cubes).

Sequence in context: A337053 A258981 A072363 * A053901 A017006 A041189

Adjacent sequences: A272881 A272882 A272883 * A272885 A272886 A272887

Keyword

nonn,base

Author

Waldemar Puszkarz, May 08 2016

Status

approved