|
|
A269605
|
|
Number of length-n 0..7 arrays with no repeated value differing from the previous repeated value by one or less.
|
|
1
|
|
|
8, 64, 504, 3962, 31024, 242226, 1886252, 14654952, 113629480, 879470154, 6796127732, 52443005888, 404170590152, 3111359345068, 23927329547328, 183840499514208, 1411335451447128, 10826702362761906, 82998453154738884
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,1
|
|
COMMENTS
|
|
|
LINKS
|
|
|
FORMULA
|
Empirical: a(n) = 31*a(n-1) -353*a(n-2) +1601*a(n-3) -435*a(n-4) -14505*a(n-5) +7118*a(n-6) +65542*a(n-7) +66279*a(n-8) +19971*a(n-9)
Empirical formula verified: see link. - Robert Israel, Jan 24 2019
|
|
EXAMPLE
|
Some solutions for n=5
..7. .4. .1. .3. .5. .2. .3. .4. .0. .1. .2. .3. .1. .5. .1. .0
..0. .1. .2. .3. .6. .0. .6. .7. .2. .2. .4. .2. .0. .6. .5. .3
..1. .1. .5. .7. .0. .6. .6. .5. .0. .6. .4. .1. .5. .0. .1. .5
..7. .2. .2. .1. .6. .5. .0. .6. .0. .2. .2. .1. .6. .4. .5. .0
..7. .0. .3. .4. .5. .0. .7. .6. .4. .6. .0. .2. .3. .2. .7. .0
|
|
MAPLE
|
with(LinearAlgebra):
T:= Matrix(72, 72):
for x from 0 to 7 do
for v from 0 to 8 do
i:= 1 + x + 8*v;
for y in {$0..7} minus {x} do
T[i, 1+y+8*v]:= 1;
od:
if abs(x-v) > 1 or v=8 then T[i, 1+x+8*x]:= 1 fi
od od:
u:= Vector([0$64, 1$8]): v:= Vector(72, 1):
Tv[1]:= v:
for n from 2 to 50 do Tv[n]:= T . Tv[n-1] od:
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|