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A268895 Decimal expansion of the upper bound of 1/Gamma(x) - x on the unit interval x = [0,1]. 4
7, 2, 1, 8, 6, 2, 7, 9, 6, 8, 2, 2, 4, 8, 1, 1, 6, 4, 9, 3, 4, 3, 7, 0, 1, 1, 4, 8, 8, 4, 6, 0, 0, 2, 8, 1, 1, 8, 7, 0, 1, 7, 7, 5, 4, 8, 9, 8, 1, 6, 1, 3, 9, 3, 8, 7, 4, 7, 3, 5, 8, 8, 3, 4, 8, 3, 9, 3, 8, 1, 4, 5, 8, 9, 1, 9, 3, 8, 6, 7, 2, 1, 5, 3, 3, 6, 3, 8, 9, 0, 2, 2, 0, 0, 8, 4, 8, 7, 6, 0, 7, 1, 0, 6 (list; constant; graph; refs; listen; history; text; internal format)
OFFSET
-1,1
COMMENTS
Gamma(x) stands for the gamma function (Euler's integral of the second kind).
On the unit interval the function 1/Gamma(x) may be bounded from below and from above as follows: x <= 1/Gamma(x) <= x + C, where C = 0.072186279... is the constant which we introduced above. Numerical simulations show that these lower and upper bounds are both quite accurate. Some other bounds for 1/Gamma(x) may be found in the reference given below.
Numerically, the value of C is quite close to the first Stieltjes constant with the opposite sign (see A082633).
LINKS
FORMULA
Equals 1/Gamma(x_0) - x_0, where x_0 is the unique positive root of the equation Gamma(x) + Psi(x) = 0 (see A268893).
EXAMPLE
0.0721862796822481164934370114884600281187017754898161...
MAPLE
Digits:= 500; x0:=fsolve(Psi(x)+GAMMA(x)=0, x): evalf(1/GAMMA(x0)-x0, 120);
MATHEMATICA
y = FindRoot[Gamma[x]+PolyGamma[x]==0, {x, 0.6}, WorkingPrecision->120][[1, 2]]; N[1/Gamma[y] - y, 120] // RealDigits[#, 10, 104] & // First
PROG
(PARI) default(realprecision, 500); x0=solve(x = 0.60, 0.68, gamma(x)+psi(x)); 1/gamma(x0)-x0
CROSSREFS
Sequence in context: A154020 A060991 A120455 * A108433 A274570 A334056
KEYWORD
nonn,cons
AUTHOR
STATUS
approved

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Last modified August 25 12:12 EDT 2024. Contains 375439 sequences. (Running on oeis4.)