A264965 Permutation of nonnegative integers: a(n) = A263273(A057889(n)).

0, 1, 2, 3, 4, 7, 6, 5, 8, 9, 10, 13, 12, 19, 22, 21, 16, 25, 18, 17, 20, 15, 26, 55, 24, 11, 14, 27, 28, 23, 30, 37, 64, 57, 46, 43, 36, 67, 70, 33, 40, 31, 66, 79, 52, 63, 38, 47, 48, 73, 58, 75, 76, 49, 54, 65, 56, 39, 34, 29, 60, 61, 74, 45, 32, 59, 42, 145, 68, 81, 226, 193, 72, 35, 82, 219, 100, 217, 174, 121, 80, 69

Offset

0,3

Comments

Perform an adjusted reverse of n in base 2, followed by another adjusted reverse in base 3. "Adjusted reverse" here means the digit-reversing operation in which the tail of trailing zeros (in the base in question) is fixed, while the portion from the most significant digit to the least significant nonzero digit is reversed.

What percentage of the cycles are finite? (See the scatter-plot and A264969, also A264972, A264973.)

Links

Antti Karttunen, Table of n, a(n) for n = 0..10000

Indranil Ghosh, Python program to generate the sequence

Formula

a(n) = A263273(A057889(n)).

Other identities. For all n >= 0:

A000035(a(n)) = A000035(n). [This permutation preserves the parity of n.]

Prog

(Scheme) (define (A264965 n) (A263273 (A057889 n)))

Crossrefs

Inverse: A264966.

Cf. A000035, A057889, A263273, A264969, A264972, A264973.

Cf. also A264967, A264968.

Sequence in context: A077223 A265369 A267308 * A266644 A329411 A055265

Adjacent sequences: A264962 A264963 A264964 * A264966 A264967 A264968

Keyword

nonn,base,look

Author

Antti Karttunen, Dec 05 2015

Status

approved