OFFSET
1,2
COMMENTS
Inspired by A008347.
a(n) - a(n-1) = 2 for n = 8.
a(11) > 10^9. - David A. Corneth, Aug 29 2018
a(13) > 7.35*10^12, if it exists. - Giovanni Resta, Sep 05 2018
LINKS
Romeo Meštrović, On the distribution of primes in the alternating sums of concecutive primes [sic], arXiv:1805.11657 [math.NT], 2018.
FORMULA
a(n) mod 2 = 1.
EXAMPLE
For first 19 prime numbers, (2 - 3 + 5 - 7 + 11 - 13 + 17 - 19 + 23 - 29 + 31 - 37 + 41 - 43 + 47 - 53 + 59 - 61 + 67) mod 19 = 38 mod 19 = 0. So a(2) = 19.
MATHEMATICA
Select[Range@ 1500, Mod[Abs@ Sum[(-1)^k Prime[# - k], {k, 0, # - 1}], #] == 0 &] (* Michael De Vlieger, Nov 27 2015, after Robert G. Wilson v at A008347 *)
PROG
(PARI) for(n=1, 1e5, if(sum(k=0, n-1, (-1)^(k)*prime(n-k)) % n == 0, print1(n, ", ")))
(PARI) upto(n) = my(s = t = 0, u=prime(n), res=List()); forprime(p=2, u, t++; s = (p - s); if(s % t == 0, listput(res, i))); res \\ David A. Corneth, Aug 29 2018
CROSSREFS
KEYWORD
nonn,more
AUTHOR
Altug Alkan, Nov 26 2015
EXTENSIONS
a(10) from David A. Corneth, Aug 29 2018
a(11)-a(12) from Giovanni Resta, Sep 03 2018
STATUS
approved