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Number of irreducible polynomials occurring as the first component of a vertex in the Fibonacci zero tree, generated as in Comments.
3

%I #8 Nov 06 2018 04:02:10

%S 0,0,1,2,3,5,8,11,21,28,54,68,135,183,360,470,948,1234,2479,3294,6531,

%T 8713,17120,23200

%N Number of irreducible polynomials occurring as the first component of a vertex in the Fibonacci zero tree, generated as in Comments.

%C The tree T, which we call the Fibonacci zero tree, is generated by these rules: (0, 0) is in T, and if (0, h) is in T, then (0, h + 1) is in T, and if (k, 0) is in T, then (0, k*x) is in T. The number of vertices (f(x),g(x)) in the n-th generation of T is F(n+1), where F = A000045, the Fibonacci numbers, for n >= 0.

%C The number of irreducible polynomials occurring as the second component of a vertex in the tree T is a(n-1) for n >= 1.

%e First few generations:

%e g(0) = {(0,0)}

%e g(1) = {(0,2), (1,0)}

%e g(2) = {(0,3), (2,0), (0,x)}

%e g(3) = {(0,4), (3,0), (0,2x), (0,1+x), (x,0)}

%e g(4) = {(0,5), (4,0), (0,3x), (0,1+2x), (2x,0), (0,2+x), (1+x,0), (0,x^2)}

%t z = 20; g = {{{0, 0}}};

%t Do[AppendTo[g, DeleteDuplicates[Partition[Flatten[Join[g, Map[# /. {{0, k_} -> {{0, k + 1}, {k, 0}}, {k_, 0} -> {0, x*k}} &, g]]], 2]]], {z}]

%t t = Table[Drop[g[[k + 1]], Length[g[[k]]]], {k, Length[g] - 1}];

%t Map[Length, t] (* Fibonacci numbers *)

%t Map[Count[IrreduciblePolynomialQ[#], {_, True}] &, t]

%t (* _Peter J. C. Moses_, Oct 19 2015 *)

%Y Cf. A000045, A264292.

%K nonn,more

%O 0,4

%A _Clark Kimberling_, Nov 24 2015