A261324 - OEIS

%I #10 Aug 17 2015 19:09:00

%S 2,3,5,3,5,7,11,11,7,5,5,11,11,11,11,7,13,13,13,29,29,7,7

%N Smallest prime p that starts an n-tuplet of consecutive primes of length A008407(n).

%C In contrast to A065688, n-tuplets here may be singular and give the complete set of residues modulo some prime. For example, for n=4 we have the 4-tuplet: (3,5,7,11) = (3,3+2,3+4,3+8), but there are no other prime 4-tuplets of the form (p,p+2,p+4,p+8), since one of its elements would be divisible by 3.

%C For any n, a(n) <= n or a(n) = A065688(n).

%F a(n) = A000040(A261323(n)).

%Y Cf. A000040, A008407, A065688, A261323.

%K nonn,more

%O 1,1

%A _Max Alekseyev_, Aug 14 2015