A261323 - OEIS

%I #11 Aug 17 2015 19:09:10

%S 1,2,3,2,3,4,5,5,4,3,3,5,5,5,5,4,6,6,6,10,10,4,4

%N Smallest m such that prime(m+n-1) - prime(m) = A008407(n); that is, prime(m) starts the smallest n-tuplet of consecutive primes of length A008407(n).

%C See A261324 for further comments and the relation to A065688.

%F a(n) = A000720(A261324(n)). - _M. F. Hasler_, Aug 17 2015

%o (PARI) A261323(n,d=A008407[n],m=0)={until(prime(m+n)==prime(m++)+d,);m} \\ Assumes a precomputed vector A008407 with at least n elements, or supply the gap as 2nd arg. Inefficient for n>23. - _M. F. Hasler_, Aug 17 2015

%Y Cf. A008407, A261324.

%K nonn,more

%O 1,2

%A _Max Alekseyev_, Aug 14 2015