

A261213


Odd numbers n such that n^2 = m + (m+1), where both m and m+1 have no repeated digits.


1



1, 3, 5, 7, 9, 11, 13, 23, 27, 29, 31, 35, 37, 39, 41, 43, 57, 63, 69, 77, 81, 87, 89, 95, 109, 113, 121, 125, 127, 129, 137, 163, 193, 219, 239, 271, 273, 279, 281, 285, 305, 311, 315, 331, 339, 353, 357, 377, 381, 395, 403, 409, 435, 441, 443, 597
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OFFSET

1,2


COMMENTS

This sequence is finite and a(146) = 40797 is the last term. 40797^2 = 1664395209 and 1664395209 = 832197604 + 832197605. These last two numbers both have no repeating digits.


LINKS

Pieter Post, Table of n, a(n) for n = 1..146


EXAMPLE

5 is in the sequence, because 5^2 = 25. 25 = 12 + 13. 12 and 13 both have no repeating digits.


MATHEMATICA

nr[n_] := 1 == Max@ DigitCount@ n; Select[ Range[1, 10^5, 2], nr[x= Floor[#^2 / 2]] && nr[x + 1] &] (* Giovanni Resta, Aug 12 2015 *)


CROSSREFS

Cf. A036745, A071519, A156977.
Sequence in context: A030155 A143448 A226484 * A130738 A239036 A024323
Adjacent sequences: A261210 A261211 A261212 * A261214 A261215 A261216


KEYWORD

nonn,full,fini,base


AUTHOR

Pieter Post, Aug 12 2015


STATUS

approved



