A261213 Odd numbers n such that n^2 = m + (m+1), where both m and m+1 have no repeated digits.

1, 3, 5, 7, 9, 11, 13, 23, 27, 29, 31, 35, 37, 39, 41, 43, 57, 63, 69, 77, 81, 87, 89, 95, 109, 113, 121, 125, 127, 129, 137, 163, 193, 219, 239, 271, 273, 279, 281, 285, 305, 311, 315, 331, 339, 353, 357, 377, 381, 395, 403, 409, 435, 441, 443, 597

Offset

1,2

Comments

This sequence is finite and a(146) = 40797 is the last term. 40797^2 = 1664395209 and 1664395209 = 832197604 + 832197605. These last two numbers both have no repeating digits.

Links

Pieter Post, Table of n, a(n) for n = 1..146

Example

5 is in the sequence, because 5^2 = 25. 25 = 12 + 13. 12 and 13 both have no repeating digits.

Mathematica

nr[n_] := 1 == Max@ DigitCount@ n; Select[ Range[1, 10^5, 2], nr[x= Floor[#^2 / 2]] && nr[x + 1] &] (* Giovanni Resta, Aug 12 2015 *)

Crossrefs

Cf. A036745, A071519, A156977.

Sequence in context: A030155 A143448 A226484 * A130738 A239036 A024323

Adjacent sequences: A261210 A261211 A261212 * A261214 A261215 A261216

Keyword

nonn,full,fini,base

Author

Pieter Post, Aug 12 2015

Status

approved