OFFSET
1,2
COMMENTS
An even number k is congruent to either 0 or 2 mod 4. If congruent to 0, it is divisible by 4 and thus not squarefree. If k is congruent to 2, k+1 will be one less than a multiple of 4, and thus at least one prime factor of k+1 will be one less than a multiple of 4. Thus, there are no even numbers in this sequence.
From the author's comment above, all sequence terms must be odd, so k+1 must always be even and k+1 will always be singly even. - Ray Chandler, Aug 03 2015
LINKS
Amiram Eldar, Table of n, a(n) for n = 1..10000
EXAMPLE
41 + 1 = 42 = 2*3*7 and both 3 and 7 are prime numbers of the form 4*n-1, so 41 is not a term of this sequence.
MATHEMATICA
Select[Range[1100], SquareFreeQ[#]&&IntegerExponent[#+1, 2]<2&&Select[First/@FactorInteger[#+1], Mod[#, 4]==3&]=={}&] (* Ray Chandler, Aug 02 2015 *)
CROSSREFS
KEYWORD
nonn
AUTHOR
J. Lowell, Aug 01 2015
STATUS
approved