

A260688


a(n) = the least number of pieces of currency of denominations .01, .05, .10, .25, 1, 5, 10, 20, 50, 100 that the greedy algorithm uses to make n times .01 (n "cents") in change.


0



0, 1, 2, 3, 4, 1, 2, 3, 4, 5, 1, 2, 3, 4, 5, 2, 3, 4, 5, 6, 2, 3, 4, 5, 6, 1, 2, 3, 4, 5, 2, 3, 4, 5, 6, 2, 3, 4, 5, 6, 3, 4, 5, 6, 7, 3, 4, 5, 6, 7, 2, 3, 4, 5, 6, 3, 4, 5, 6, 7, 3, 4, 5, 6, 7, 4, 5, 6, 7, 8, 4, 5, 6, 7, 8, 3, 4, 5, 6, 7, 4, 5, 6, 7, 8, 4, 5, 6, 7, 8, 5, 6, 7, 8, 9, 5, 6, 7, 8, 9
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OFFSET

0,3


LINKS

Table of n, a(n) for n=0..99.
US Treasury, Denominations of Coins
US Treasury, Denominations of Paper Currency


PROG

(Python)
def how_many(cents):
#d = denominations
d = ['$0.01', '$0.05', '$0.10', '$0.25',
'$1', '$5', '$10', '$20', '$50', '$100']
coins = {coin: 100*float(str(coin)[1:]) for coin in d}
how_many = {d[i]: 0 for i in range(10)}
while len(d) != 0:
how_many[d[1]] = cents // coins[d[1]]
cents %= coins[d[1]]
d.pop()
return int(sum(how_many.values()))


CROSSREFS

Cf. A067997, A080897, A108536.
Sequence in context: A053840 A010883 A011542 * A053344 A092196 A100878
Adjacent sequences: A260685 A260686 A260687 * A260689 A260690 A260691


KEYWORD

nonn


AUTHOR

Edward Minnix III, Nov 15 2015


EXTENSIONS

Edited by N. J. A. Sloane, Apr 24 2016


STATUS

approved



