|
|
A260465
|
|
a(n) is the smallest number not already in the sequence such that a(n)^3 begins with n.
|
|
1
|
|
|
1, 3, 7, 16, 8, 4, 9, 2, 21, 10, 48, 5, 11, 52, 25, 55, 12, 57, 27, 59, 6, 61, 62, 29, 63, 64, 14, 66, 31, 67, 68, 32, 15, 70, 33, 154, 72, 73, 34, 74, 161, 35, 76, 164, 77, 36, 78, 169, 17, 37, 80, 174, 81, 38, 82, 178, 83, 18, 39, 182, 85, 184, 86, 40, 87, 188, 189, 19, 191, 89, 193, 90, 194, 42, 91, 197, 92, 199, 43
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,2
|
|
COMMENTS
|
Conjectured to be a permutation of the natural numbers.
|
|
LINKS
|
|
|
FORMULA
|
a(n) >= n^(1/3) for all n > 0. If a(n) = n^(1/3), then n is a cube. Note the converse is false: a(27) = 14.
|
|
PROG
|
(PARI) v=[]; k=1; while(#v<100, d=digits(k^3); D=digits(#v+1); if(#D<=#d, c=1; for(i=1, #D, if(D[i]!=d[i], c=0; break)); if(c&&!vecsearch(vecsort(v), k), v=concat(v, k); k=0)); k++); v
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn,base
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|