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 A259599 Infinite palindromic word (a(1),a(2),a(3),...) with initial word w(1) = (1,0,1) and midword sequence (a(n)); see Comments. 4
 1, 0, 1, 1, 1, 0, 1, 0, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 0, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 0, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 0, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 0, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1 COMMENTS Below, w* denotes the reversal of a word w, and "sequence" and "word" are interchangable. An infinite word is palindromic if it has infinitely many initial subwords w such that w = w*. Many infinite palindromic words (a(1),a(2),...) are determined by an initial word w and a midword sequence (m(1),m(2),...) of palindromes, as follows: for given w of length k, take w(1) = w = (a(1),a(2),...,a(k)). Form the palindrome w(2) = w(1)m(1)w(1)* by concatenating w(1), m(1), and w(1)*. Continue inductively; i.e., w(n+1) = w(n)m(n)w(n)* for all n >= 1. See A260390 for examples. a(n) = A035263(n) for n=1..31, but not n=32. LINKS Clark Kimberling, Table of n, a(n) for n = 1..10000 FORMULA a(n) = 1 - A260446(n). EXAMPLE w(1) = 101, the initial word; w(2) = 1011101 ( = 101+1+101, where + = concatenation); w(3) = w(2)+0+w(2)* = 101110101011101; w(4) = w(3)+1+w(3)*. MATHEMATICA u[1] = {1, 0, 1}; m[1] = {u[1][[1]]}; u[n_] := u[n] = Join[u[n - 1], m[n - 1], Reverse[u[n - 1]]]; m[k_] := {u[k][[k]]}; u[6] CROSSREFS Cf. A260390, A260446. Sequence in context: A029883 A035263 A089045 * A070749 A285341 A059778 Adjacent sequences:  A259596 A259597 A259598 * A259600 A259601 A259602 KEYWORD nonn,easy AUTHOR Clark Kimberling, Aug 13 2015 STATUS approved

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Last modified March 28 19:39 EDT 2020. Contains 333103 sequences. (Running on oeis4.)