OFFSET
1,1
COMMENTS
It seems that for all n >= 1, Sum_{k=1 .. 2^n} a(k) = 2^(n+3) - 1 = A000225(n+3).
LINKS
Antti Karttunen, Table of n, a(n) for n = 1..16384
CROSSREFS
KEYWORD
nonn
AUTHOR
Antti Karttunen, May 03 2015
STATUS
approved