%I #10 Mar 08 2015 04:21:24
%S 1,5,18,61,182,506,1338,3369,8172,19197,43833,97636,212748,454461,
%T 953505,1968095,4001627,8024295,15885484,31074351,60111277,115071431,
%U 218126868,409662895,762679151,1408172844,2579599582,4690277001,8467363674,15182486586
%N G.f.: Product_{k>=1} (1+x^k)^(3*k+2).
%C In general, if g.f. = Product_{k>=1} (1+x^k)^(m*k+c), m > 0, then a(n) ~ (m*Zeta(3))^(1/6) * exp(-c^2 * Pi^4 / (1296*m*Zeta(3)) + (c * Pi^2 * n^(1/3)) / (2^(5/3) * 3^(4/3) * (m*Zeta(3))^(1/3)) + 3^(4/3) * (m*Zeta(3))^(1/3) * n^(2/3) / 2^(4/3)) / (2^(m/12 + c/2 + 2/3) * 3^(1/3) * sqrt(Pi) * n^(2/3)). - _Vaclav Kotesovec_, Mar 08 2015
%H Vaclav Kotesovec, <a href="/A255837/b255837.txt">Table of n, a(n) for n = 0..1000</a>
%F a(n) ~ Zeta(3)^(1/6) * exp(-Pi^4/(972*Zeta(3)) + Pi^2 * n^(1/3) / (2^(2/3) * 3^(5/3) * Zeta(3)^(1/3)) + 3^(5/3)/2^(4/3) * Zeta(3)^(1/3) * n^(2/3)) / (2^(23/12) * 3^(1/6) * sqrt(Pi) * n^(2/3)), where Zeta(3) = A002117.
%t nmax=50; CoefficientList[Series[Product[(1+x^k)^(3*k+2),{k,1,nmax}],{x,0,nmax}],x]
%Y Cf. A026007 (k), A219555 (k+1), A052812 (k-1), A255834 (2*k+1), A255835 (2*k-1), A255836 (3*k+1).
%Y Cf. A255803.
%K nonn
%O 0,2
%A _Vaclav Kotesovec_, Mar 07 2015