

A254617


Least positive integer m such that A254574(m) = n


3



49, 1, 3, 20, 8, 15, 30, 22, 58, 48, 93, 78, 92, 148, 113, 127, 155, 198, 197, 323, 268, 272, 288, 345, 358, 338, 555, 568, 443, 498, 612, 547, 653, 730, 708, 687, 722, 778, 1002, 897, 1107, 1030, 1112, 1205, 1535, 1343, 1458, 1093, 1203, 1588, 1548, 1822, 1623, 2162, 2208, 1577, 1497, 1948, 2228, 2473
(list;
graph;
refs;
listen;
history;
text;
internal format)



OFFSET

1,1


COMMENTS

Conjecture: (i) a(n) exists for any n > 0. Also, the main term of a(n) is n^2/2 as n tends to the infinity.
(ii) No term a(n) with n>2 is congruent to 1 or 1 modulo 5.
See also the comments in A254595 for a similar conjecture.


LINKS



EXAMPLE

a(4) = 20 since 20 is the first positive integer m with A254574(m) = 4. Note that 20 = 0*1/2 + 3*(3*3+1)/2 + 2*(3*21)/2 = 1*2/2 + 2*(3*2+1)/2 + 3*(3*31)/2 = 3*4/2 + 1*(3*1+1)/2 + 3*(3*31)/2 = 5*6/2 + 0*(3*0+1)/2 + 2*(3*21)/2.


MATHEMATICA

TQ[n_]:=IntegerQ[Sqrt[8n+1]]
Do[Do[m=0; Label[aa]; m=m+1; r=0; Do[If[TQ[my(3y+1)/2z(3z1)/2], r=r+1; If[r>n, Goto[aa]]], {y, 0, (Sqrt[24m+1]1)/6}, {z, 0, (Sqrt[24(my(3y+1)/2)+1]+1)/6}];
If[r==n, Print[n, " ", m]; Goto[bb], Goto[aa]]]; Label[bb]; Continue, {n, 1, 60}]


CROSSREFS



KEYWORD

nonn


AUTHOR



STATUS

approved



