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A249360 Number of length 1+6 0..n arrays with every seven consecutive terms having six times some element equal to the sum of the remaining six 1
2, 395, 2048, 9413, 30848, 84259, 198570, 421913, 823336, 1504241, 2601366, 4297747, 6831608, 10505741, 15697544, 22873679, 32598374, 45551245, 62537376, 84505589, 112561702, 147987947, 192258132, 247057213, 314300264, 396153407 (list; graph; refs; listen; history; text; internal format)
OFFSET

1,1

COMMENTS

Row 1 of A249359

LINKS

R. H. Hardin, Table of n, a(n) for n = 1..54

FORMULA

Empirical: a(n) = 5*a(n-1) -11*a(n-2) +15*a(n-3) -15*a(n-4) +12*a(n-5) -9*a(n-6) +7*a(n-7) -4*a(n-8) +4*a(n-10) -7*a(n-11) +9*a(n-12) -12*a(n-13) +15*a(n-14) -15*a(n-15) +11*a(n-16) -5*a(n-17) +a(n-18)

Also a polynomial of degree 6 plus a quasipolynomial of degree 0 with period 60, the first 12 being:

Empirical for n mod 60 = 0: a(n) = (7/6)*n^6 + (14/5)*n^5 + (21/4)*n^4 + (14/3)*n^3 + (7/2)*n^2 + n + 1

Empirical for n mod 60 = 1: a(n) = (7/6)*n^6 + (14/5)*n^5 + (21/4)*n^4 + (14/3)*n^3 + (7/2)*n^2 + n - (983/60)

Empirical for n mod 60 = 2: a(n) = (7/6)*n^6 + (14/5)*n^5 + (21/4)*n^4 + (14/3)*n^3 + (7/2)*n^2 + n + (467/5)

Empirical for n mod 60 = 3: a(n) = (7/6)*n^6 + (14/5)*n^5 + (21/4)*n^4 + (14/3)*n^3 + (7/2)*n^2 + n - (1373/20)

Empirical for n mod 60 = 4: a(n) = (7/6)*n^6 + (14/5)*n^5 + (21/4)*n^4 + (14/3)*n^3 + (7/2)*n^2 + n + (967/15)

Empirical for n mod 60 = 5: a(n) = (7/6)*n^6 + (14/5)*n^5 + (21/4)*n^4 + (14/3)*n^3 + (7/2)*n^2 + n - (353/4)

Empirical for n mod 60 = 6: a(n) = (7/6)*n^6 + (14/5)*n^5 + (21/4)*n^4 + (14/3)*n^3 + (7/2)*n^2 + n + (551/5)

Empirical for n mod 60 = 7: a(n) = (7/6)*n^6 + (14/5)*n^5 + (21/4)*n^4 + (14/3)*n^3 + (7/2)*n^2 + n - (7871/60)

Empirical for n mod 60 = 8: a(n) = (7/6)*n^6 + (14/5)*n^5 + (21/4)*n^4 + (14/3)*n^3 + (7/2)*n^2 + n + (1013/5)

Empirical for n mod 60 = 9: a(n) = (7/6)*n^6 + (14/5)*n^5 + (21/4)*n^4 + (14/3)*n^3 + (7/2)*n^2 + n - (3109/20)

Empirical for n mod 60 = 10: a(n) = (7/6)*n^6 + (14/5)*n^5 + (21/4)*n^4 + (14/3)*n^3 + (7/2)*n^2 + n + (143/3)

Empirical for n mod 60 = 11: a(n) = (7/6)*n^6 + (14/5)*n^5 + (21/4)*n^4 + (14/3)*n^3 + (7/2)*n^2 + n + (1819/20)

EXAMPLE

Some solutions for n=6

..3....0....3....2....0....2....4....6....1....2....2....4....4....6....5....6

..3....2....5....6....0....4....0....6....6....3....0....3....2....6....5....3

..4....0....4....0....6....5....6....6....0....4....3....3....5....4....3....0

..4....4....1....0....3....5....6....1....2....1....3....6....5....5....3....4

..5....3....0....0....3....3....6....4....2....5....5....3....2....1....6....3

..3....5....4....2....0....6....2....3....2....3....6....2....6....2....4....3

..6....0....4....4....2....3....4....2....1....3....2....0....4....4....2....2

CROSSREFS

Sequence in context: A249359 A249255 A249171 * A249361 A249362 A249363

Adjacent sequences:  A249357 A249358 A249359 * A249361 A249362 A249363

KEYWORD

nonn

AUTHOR

R. H. Hardin, Oct 26 2014

STATUS

approved

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Last modified May 24 21:08 EDT 2022. Contains 354043 sequences. (Running on oeis4.)