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0, 7, 2439, 2439111, 5358727111, 21949346247111, 150550565908935111, 1603062425798341063111, 25047850403099079111111111, 549850412048830984647111111111, 16380593625346723863622087111111111
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OFFSET
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0,2
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COMMENTS
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These are the numerators of the partial sums S(n) = Sum_{k=1..n} (3k^3+3k^2+k)/A007559(k+1)^2 before simplification, i.e., a(n) = S(n)*A007559(n+1)^2. The series S(n) has sum 1/9, actually S(n) = 1/9 - 1/(9*A007559(n+1)^2).
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LINKS
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PROG
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(PARI) a(n)=(prod(k=1, n, 3*k+1)^3-1)/9
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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