A248566 Numbers k such that A248565(k+1) = A248565(k) + 1.

1, 2, 4, 5, 7, 8, 10, 12, 14, 15, 17, 19, 21, 23, 25, 27, 29, 30, 32, 34, 36, 38, 40, 42, 44, 46, 48, 50, 52, 54, 56, 58, 59, 61, 63, 65, 67, 69, 71, 73, 75, 77, 79, 81, 83, 85, 87, 89, 91, 93, 95, 97, 99, 101, 103, 105, 107, 109, 111, 113, 115, 116, 118

Offset

1,2

Links

Clark Kimberling, Table of n, a(n) for n = 1..500

Example

(A248565(k+1) - A248565(k)) = (1, 1, 2, 1, 1, 2, 1, 1, 2, 1, 2, 1, 2, 1, 1, 2, 1, 2,...), so that A248566 = (1, 2, 4, 5, 7, 8, 10, 12, 14, ..) and A248567 = (3, 6, 9, 11, 13, 16, 18, 20, ...).

Mathematica

z = 2500; p[k_] := p[k] = Sum[1/(h*4^h), {h, 1, k}];
N[Table[p[k], {k, 1, z/5}], 12];
N[Table[Log[4/3] - p[n], {n, 1, z/5}]];
f[n_] := f[n] = Select[Range[z], Log[4/3] - p[#] < 1/8^n &, 1];
u = Flatten[Table[f[n], {n, 1, z}]] ;   (* A248565 *)
Flatten[Position[Differences[u], 1]];   (* A248566 *)
Flatten[Position[Differences[u], 2]];   (* A248567 *)

Crossrefs

Cf. A248565, A248567, A248560, A248563.

Sequence in context: A174131 A014248 A174799 * A091627 A160830 A363761

Adjacent sequences: A248563 A248564 A248565 * A248567 A248568 A248569

Keyword

nonn,easy

Author

Clark Kimberling, Oct 09 2014

Status

approved