A248450 - OEIS

The OEIS is supported by the many generous donors to the OEIS Foundation.

Year-end appeal: Please make a donation to the OEIS Foundation to support ongoing development and maintenance of the OEIS. We are now in our 60th year, we have over 367,000 sequences, and we’ve reached 11,000 citations (which often say “discovered thanks to the OEIS”).

Other ways to Give

A248450

Number of length 2+5 0..n arrays with no three disjoint pairs in any consecutive six terms having the same sum

62, 1272, 11436, 59480, 226410, 694632, 1824272, 4257336, 9061830, 17909120, 33303852, 58859112, 99630266, 162505920, 256670520, 394127072, 590308422, 864758736, 1241905340, 1751918880, 2431676802, 3325811912, 4487885496 (list; graph; refs; listen; history; text; internal format)

	OFFSET	`1,1`
	COMMENTS	`Row 2 of A248448`
	LINKS	`R. H. Hardin, Table of n, a(n) for n = 1..54`
	FORMULA	`Empirical: a(n) = 4a(n-1) -5a(n-2) +2a(n-3) -2a(n-4) +2a(n-5) +5a(n-6) -8a(n-7) +6a(n-8) -8a(n-9) +5a(n-10) +2a(n-11) -2a(n-12) +2a(n-13) -5a(n-14) +4a(n-15) -a(n-16)` `Empirical for n mod 12 = 0: a(n) = n^7 + 7n^6 + 6n^5 + (55/2)n^4 + (415/9)n^3 - (383/3)n^2 + 74n` `Empirical for n mod 12 = 1: a(n) = n^7 + 7n^6 + 6n^5 + (55/2)n^4 + (415/9)n^3 - (383/3)n^2 + 89n + (235/18)` `Empirical for n mod 12 = 2: a(n) = n^7 + 7n^6 + 6n^5 + (55/2)n^4 + (415/9)n^3 - (383/3)n^2 + (142/3)n + (1000/9)` `Empirical for n mod 12 = 3: a(n) = n^7 + 7n^6 + 6n^5 + (55/2)n^4 + (415/9)n^3 - (383/3)n^2 + 89n + (195/2)` `Empirical for n mod 12 = 4: a(n) = n^7 + 7n^6 + 6n^5 + (55/2)n^4 + (415/9)n^3 - (383/3)n^2 + 74n + (320/9)` `Empirical for n mod 12 = 5: a(n) = n^7 + 7n^6 + 6n^5 + (55/2)n^4 + (415/9)n^3 - (383/3)n^2 + (187/3)n + (1595/18)` `Empirical for n mod 12 = 6: a(n) = n^7 + 7n^6 + 6n^5 + (55/2)n^4 + (415/9)n^3 - (383/3)n^2 + 74n` `Empirical for n mod 12 = 7: a(n) = n^7 + 7n^6 + 6n^5 + (55/2)n^4 + (415/9)n^3 - (383/3)n^2 + 89n + (2395/18)` `Empirical for n mod 12 = 8: a(n) = n^7 + 7n^6 + 6n^5 + (55/2)n^4 + (415/9)n^3 - (383/3)n^2 + (142/3)n + (1000/9)` `Empirical for n mod 12 = 9: a(n) = n^7 + 7n^6 + 6n^5 + (55/2)n^4 + (415/9)n^3 - (383/3)n^2 + 89n - (45/2)` `Empirical for n mod 12 = 10: a(n) = n^7 + 7n^6 + 6n^5 + (55/2)n^4 + (415/9)n^3 - (383/3)n^2 + 74n + (320/9)` `Empirical for n mod 12 = 11: a(n) = n^7 + 7n^6 + 6n^5 + (55/2)n^4 + (415/9)n^3 - (383/3)n^2 + (187/3)*n + (3755/18)`
	EXAMPLE	`Some solutions for n=4` `..3....0....3....1....3....0....1....2....2....1....4....3....3....1....3....2` `..0....1....0....4....4....1....0....1....1....2....2....1....0....2....4....4` `..2....4....1....4....0....1....2....1....0....1....2....0....1....0....0....0` `..2....0....3....3....3....3....3....3....3....0....3....3....0....3....4....3` `..3....2....4....3....4....3....1....0....0....3....0....0....2....1....1....4` `..1....1....2....0....3....3....4....0....1....3....3....0....0....0....3....0` `..0....4....3....3....4....4....3....3....0....3....1....0....0....1....3....2`
	CROSSREFS	`Sequence in context: A250564 A231027 A103428 * A115504 A296359 A037962` `Adjacent sequences: A248447 A248448 A248449 * A248451 A248452 A248453`
	KEYWORD	`nonn`
	AUTHOR	`R. H. Hardin, Oct 06 2014`
	STATUS	`approved`

License Agreements, Terms of Use, Privacy Policy. .

Last modified December 2 20:20 EST 2023. Contains 367526 sequences. (Running on oeis4.)