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 A248232 Numbers k such that A248231(k+1) = A248231(k). 4
 1, 4, 8, 11, 15, 18, 22, 25, 28, 32, 35, 39, 42, 46, 49, 52, 56, 59, 63, 66, 69, 73, 76, 80, 83, 87, 90, 93, 97, 100, 104, 107, 110, 114, 117, 121, 124, 128, 131, 134, 138, 141, 145, 148, 151, 155, 158, 162, 165, 168, 172, 175, 179, 182, 186, 189, 192, 196 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,2 COMMENTS Since A248231(k+1) - A248232(k) is in {0,1} for k >= 1, A248232 and A248233 are complementary. LINKS Clark Kimberling, Table of n, a(n) for n = 1..500 EXAMPLE The difference sequence of A248231 is (0, 1, 1, 0, 1, 1, 1, 0, 1, 1, 0, 1, 1, 1, 0, 1, 1, 0, 1, 1, 1, 0, 1, ...), so that A248232 = (1, 4, 8, 11, 15, 18, 22, 25, 28,...) and A248233 = (2, 3, 5, 6, 7, 9, 10, 12, 13, 14, 16, 17,...), the complement of A248232. MATHEMATICA z = 400; p[k_] := p[k] = Sum[1/h^5, {h, 1, k}]; N[Table[Zeta[5] - p[n], {n, 1, z/10}]] f[n_] := f[n] = Select[Range[z], Zeta[5] - p[#] < 1/n^4 &, 1] u = Flatten[Table[f[n], {n, 1, z}]] (* A248231 *) Flatten[Position[Differences[u], 0]] (* A248232 *) Flatten[Position[Differences[u], 1]] (* A248233 *) Table[Floor[1/(Zeta[5] - p[n])], {n, 1, z}] (* A248234 *) CROSSREFS Cf. A248231, A248233, A248234, A248227. Sequence in context: A311049 A073302 A191105 * A047346 A198270 A214971 Adjacent sequences: A248229 A248230 A248231 * A248233 A248234 A248235 KEYWORD nonn,easy AUTHOR Clark Kimberling, Oct 05 2014 STATUS approved

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Last modified August 13 09:05 EDT 2024. Contains 375118 sequences. (Running on oeis4.)