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Numbers n such that A033493(n)/A008908(n) is an integer.
0

%I #6 Sep 25 2014 21:46:23

%S 1,5,18,58,99,153,176,228,238,240,282,341,345,421,475,585,629,712,739,

%T 779,802,815,974,995,1078,1088,1237,1257,1262,1290,1346,1398,1424,

%U 1459,1673,1694,1724,1731,1802,1811,1916,1928,1988,2170,2222,2260,2272,2275,2317,2365,2397,2410

%N Numbers n such that A033493(n)/A008908(n) is an integer.

%C Equivalently, these are also numbers n such that the average of the numbers in the Collatz (3x+1) iteration of n is an integer.

%o (PARI)

%o Tavg(n)=c=0;s=n;while(n!=1,if(n==Mod(0,2),n=n/2;c++;s+=n);if(n==Mod(1,2)&&n!=1,n=3*n+1;s+=n;c++));s/(c+1)

%o n=1;while(n<10^4,if(floor(Tavg(n))==Tavg(n),print1(n,", "));n++)

%Y Cf. A008908, A033493.

%K nonn

%O 1,2

%A _Derek Orr_, Sep 22 2014