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%I #32 Feb 19 2024 21:49:04
%S 1,1,0,0,1,4,17,80,422,2480,16095,114432,884969,7398464,66502048,
%T 639653632,6556170841,71340409600,821408397105,9977630263296,
%U 127518757153174,1710576547456000,24030971882538671,352843606806499328
%N Number of 2-alternating permutations of 1,2,...,n, that is, a(n) is the number of down/up permutations (A000111) of 1,2,...,n such that any two consecutive terms differ by at least two.
%e For n=5 there are the four permutations 31425, 31524, 52413, 42513.
%p b:= proc(n, s, t) option remember; `if`(s={}, 1, add(
%p `if`(t*(n-j)>=2, b(j, s minus{j}, -t), 0), j=s))
%p end:
%p a:= n->`if`(n=0, 1, add(b(j, {$1..j-1, $j+1..n}, 1), j=1..n)):
%p seq(a(n), n=0..16); # _Alois P. Heinz_, Oct 27 2014
%t b[n_, s_, t_] := b[n, s, t] = If[s == {}, 1, Sum[If[t*(n - j) >= 2, b[j, s ~Complement~ {j}, -t], 0], {j, s}]]; a[n_] := a[n] = If[n == 0, 1, Sum[b[j, DeleteCases[Range[n], j], 1], {j, 1, n}]]; Table[Print[a[n]]; a[n], {n, 0, 16}] (* _Jean-François Alcover_, Oct 24 2016, after _Alois P. Heinz_ *)
%o (C++) #include <iostream>
%o #include <algorithm>
%o #include <vector>
%o using namespace std;
%o bool isA245377(const vector<int> per)
%o {
%o bool good=true;
%o for(int i=0 ; i < per.size() -1 && good ;i++)
%o {
%o if( abs(per[i]-per[i+1]) < 2 )
%o good = false;
%o else
%o {
%o if ( i %2 )
%o {
%o if ( per[i+1] > per[i])
%o good = false;
%o }
%o else
%o {
%o if ( per[i+1] < per[i])
%o good = false;
%o }
%o }
%o }
%o return good ;
%o }
%o int A245377(const int n)
%o {
%o vector<int> per(n) ;
%o for(int i=0 ; i < n ; i++)
%o per[i] = i+1 ;
%o int a= isA245377(per) ? 1 : 0 ;
%o while( next_permutation(per.begin(),per.end()) )
%o {
%o if ( isA245377(per) )
%o a++ ;
%o }
%o return a;
%o }
%o int main(int argc, char *argv[])
%o {
%o for (int n=1 ; ; n++)
%o cout << A245377(n) << endl ;
%o } // _R. J. Mathar_, Oct 25 2014
%Y Cf. A002464.
%K nonn,more
%O 0,6
%A _Richard Stanley_, Jul 19 2014
%E a(11)-a(15) from _R. J. Mathar_, Oct 27 2014
%E a(16)-a(21) from _Alois P. Heinz_, Oct 27 2014
%E a(22) from _Alois P. Heinz_, Feb 18 2024
%E a(23) from _Max Alekseyev_, Feb 19 2024