

A244852


Least number k > 0 such that 3^k begins with exactly n consecutive increasing digits.


3




OFFSET

1,2


LINKS

Table of n, a(n) for n=1..9.


EXAMPLE

3^17 = 129140163 begins with 2 consecutive increasing digits ('12'). Thus a(2) = 17.


PROG

(Python)
def a(n):
..for k in range(1, 10**5):
....st = str(3**k)
....count = 0
....if len(st) > n:
......for i in range(len(st)):
........if int(st[i]) == int(st[i+1])1:
..........count += 1
........else:
..........break
......if count == n:
........return k
n = 0
while n < 10:
..print(a(n), end=', ')
..n += 1


CROSSREFS

Cf. A244848, A244849, A244851.
Sequence in context: A196780 A208506 A299599 * A064102 A161497 A162328
Adjacent sequences: A244849 A244850 A244851 * A244853 A244854 A244855


KEYWORD

nonn,base,fini,full


AUTHOR

Derek Orr, Jul 07 2014


EXTENSIONS

a(7)a(9) from Hiroaki Yamanouchi, Jul 10 2014


STATUS

approved



