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 A244251 Numbers k such that if m = (sum of the reverses of the aliquot parts of k) then k = (sum of the reverses of the aliquot parts of m). 1
 6, 98, 145, 244, 285, 133857 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,1 COMMENTS A072228 is a subsequence of this sequence. LINKS EXAMPLE Aliquot parts of 98 are 1, 2, 7, 14, 49 and the sum of their reverses is 1 + 2 + 7 + 41 + 94 = 145. Aliquot parts of 145 are 1, 5, 29 and the sum of their reverses is 1 + 5 + 92 = 98. MAPLE with(numtheory): T:=proc(w) local x, y, z; x:=0; y:=w; for z from 1 to ilog10(w)+1 do x:=10*x+(y mod 10); y:=trunc(y/10); od; x; end: P:=proc(q) local a, b, k, n; for n from 1 to q do a:=sort([op(divisors(n))]); b:=add(T(a[k]), k=1..nops(a)-1); a:=sort([op(divisors(b))]); b:=add(T(a[k]), k=1..nops(a)-1); if b=n then print(n); fi; od; end: P(10^12); CROSSREFS Cf. A072228. Sequence in context: A288544 A064753 A322739 * A187522 A224615 A138913 Adjacent sequences:  A244248 A244249 A244250 * A244252 A244253 A244254 KEYWORD nonn,more,base AUTHOR Paolo P. Lava, Dec 09 2014 STATUS approved

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Last modified August 17 23:13 EDT 2022. Contains 356204 sequences. (Running on oeis4.)