A243359 Number of steps it takes the terms in A029742 and their reversals to reach the value 9 when the smaller term is successively subtracted from the larger term.

1, 1, 5, 3, 4, 2, 2, 4, 3, 5, 1, 1, 5, 3, 4, 2, 2, 4, 3, 5, 1, 1, 5, 3, 4, 2, 2, 4, 3, 5, 1, 1, 5, 3, 4, 2, 2, 4, 3, 5, 1, 1, 5, 3, 4, 2, 2, 4, 3, 5, 1, 1, 5, 3, 4, 2, 2, 4, 3, 5, 1, 1, 5, 3, 4, 2, 2, 4, 3, 5, 1, 1, 5, 3, 4, 2, 2, 4, 3, 5, 1

Offset

1,3

Comments

Sequence appears to be periodic with period 10, although I don't have a proof for this property.

If the successive subtraction algorithm is applied to the terms of A002113, the resulting value is always 0 after one iteration, therefore only the values resulting from the terms of that sequence's complement A029742 are taken into account for this sequence.

Links

Table of n, a(n) for n=1..81.

Example

For 14: 41 - 14 = 27 --> 72 - 27 = 45 --> 54 - 45 = 9 takes three steps to reach 9, therefore a(4) = 3.

Crossrefs

Sequence in context: A293509 A090343 A135448 * A222229 A168360 A342116

Adjacent sequences: A243356 A243357 A243358 * A243360 A243361 A243362

Keyword

nonn,base

Author

Felix Fröhlich, Jun 03 2014

Extensions

Extended by Ray Chandler, Aug 27 2015

Status

approved