

A243359


Number of steps it takes the terms in A029742 and their reversals to reach the value 9 when the smaller term is successively subtracted from the larger term.


0



1, 1, 5, 3, 4, 2, 2, 4, 3, 5, 1, 1, 5, 3, 4, 2, 2, 4, 3, 5, 1, 1, 5, 3, 4, 2, 2, 4, 3, 5, 1, 1, 5, 3, 4, 2, 2, 4, 3, 5, 1, 1, 5, 3, 4, 2, 2, 4, 3, 5, 1, 1, 5, 3, 4, 2, 2, 4, 3, 5, 1, 1, 5, 3, 4, 2, 2, 4, 3, 5, 1, 1, 5, 3, 4, 2, 2, 4, 3, 5, 1
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OFFSET

1,3


COMMENTS

Sequence appears to be periodic with period 10, although I don't have a proof for this property.
If the successive subtraction algorithm is applied to the terms of A002113, the resulting value is always 0 after one iteration, therefore only the values resulting from the terms of that sequence's complement A029742 are taken into account for this sequence.


LINKS



EXAMPLE

For 14: 41  14 = 27 > 72  27 = 45 > 54  45 = 9 takes three steps to reach 9, therefore a(4) = 3.


CROSSREFS



KEYWORD

nonn,base


AUTHOR



EXTENSIONS



STATUS

approved



