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A242565
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Numbers k such that (k!+1)/(k+1) is prime.
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1
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OFFSET
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1,1
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COMMENTS
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It is unknown whether this sequence is infinite. If S = (n!+k)/(n+k), when k > 1, there are finitely many n-values that make S an integer. When k = 1, there are infinitely many n-values that make S an integer (A006093).
a(8) > 4725.
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LINKS
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EXAMPLE
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(4!+1)/(4+1) = 5 is prime. Thus, 4 is a member of this sequence.
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MATHEMATICA
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ParallelTable[If[PrimeQ[(Factorial[n]+1)/(n+1)], n, Nothing], {n, 1, 5*10^3}]//.{}->Nothing (* J.W.L. (Jan) Eerland, Aug 15 2022 *)
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PROG
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(PARI) for(n=1, 5000, s=((prime(n)-1)!+1)/(prime(n)); if(ispseudoprime(s), print1(prime(n)-1)))
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CROSSREFS
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KEYWORD
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nonn,more,hard,changed
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AUTHOR
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STATUS
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approved
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