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A240313 Number of partitions p of n such that (maximal multiplicity of the parts of p) >= (maximal part of p). 5

%I #8 Dec 25 2023 17:38:26

%S 1,1,1,1,3,3,5,5,8,11,15,19,27,32,43,53,70,84,112,135,174,212,268,324,

%T 407,490,606,731,897,1075,1312,1567,1899,2265,2726,3238,3886,4598,

%U 5486,6482,7698,9063,10727,12592,14846,17391,20427,23862,27952,32568,38033

%N Number of partitions p of n such that (maximal multiplicity of the parts of p) >= (maximal part of p).

%F a(n) = A240312(n) + A240314(n) for n >= 0.

%F a(n) + A240310(n) = A000041(n) for n >= 0.

%e a(6) counts these 5 partitions: 3111, 222, 2211, 21111, 111111.

%t z = 60; f[n_] := f[n] = IntegerPartitions[n]; m[p_] := Max[Map[Length, Split[p]]] (* maximal multiplicity *)

%t Table[Count[f[n], p_ /; m[p] < Max[p]], {n, 0, z}] (* A240310 *)

%t Table[Count[f[n], p_ /; m[p] <= Max[p]], {n, 0, z}] (* A240311 *)

%t Table[Count[f[n], p_ /; m[p] == Max[p]], {n, 0, z}] (* A240312 *)

%t Table[Count[f[n], p_ /; m[p] >= Max[p]], {n, 0, z}] (* A240313 *)

%t Table[Count[f[n], p_ /; m[p] > Max[p]], {n, 0, z}] (* A240314 *)

%Y Cf. A240310, A240311, A240312, A240314, A000041, A118053.

%K nonn,easy

%O 0,5

%A _Clark Kimberling_, Apr 05 2014

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Last modified May 2 23:14 EDT 2024. Contains 372203 sequences. (Running on oeis4.)