%I #33 Jul 04 2024 20:18:14
%S 2,9,170,4023,632148,4843161124,1981162639374
%N Smallest integer m such that the n consecutive numbers m, m+1, ..., m+n-1 have n prime factors each, counted with multiplicity; a(n) = 0 if no such number exists.
%t Table[First@Select[Range[10^6],Union[PrimeOmega[(#+Range[n]-1)]]==={n}&,1],{n,5}] (* _Wouter Meeussen_, Feb 09 2014 *)
%t With[{po=PrimeOmega[Range[633000]]},Table[SequencePosition[po,PadRight[{},n,n],1][[1,1]],{n,5}]] (* Requires Mathematica version 10 or later *) (* The program generates the first 5 terms of the sequence. *) (* _Harvey P. Dale_, Jun 15 2021 *)
%o (Python)
%o import sympy
%o from sympy import isprime
%o from sympy import factorint
%o def PrimeFact(x):
%o n = 9930000
%o lst = []
%o while n < 10**10:
%o if not isprime(n):
%o count = 0
%o for i in range(n, n+x):
%o if sum(factorint(i).values()) == x:
%o count += 1
%o else:
%o n += 1
%o break
%o if count == x:
%o return n
%o else:
%o n += 1
%o (PARI) for(n=1, 5, for(k=2^n-1, oo, my(found=1); for(j=1, n, if(bigomega(k+j)!=n, found=0; break)); if(found, print1(k+1,", "); break))) \\ _Hugo Pfoertner_, Oct 21 2020
%Y Cf. A001222.
%K nonn,hard,more
%O 1,1
%A _Derek Orr_, Feb 04 2014
%E a(6) from _Giovanni Resta_, Feb 09 2014
%E a(7) from _Giovanni Resta_, Feb 10 2014