login
Period of the n-th convergent to the continued fraction expansion of Pi.
1

%I #24 Nov 19 2023 21:15:59

%S 1,6,13,112,51,24,15088,12284,88460,1204,459,31824,93210,1864254,

%T 531648,456036,8299090,28574910,1813560,32552820,33166008,133585180,

%U 2503410,214098720,3183870690,7411133309730,4852769490690,2294509753536,175964053944,3336533898768

%N Period of the n-th convergent to the continued fraction expansion of Pi.

%F a(n) = A007732(A002486(n+2)). - _Michel Marcus_, Jan 21 2014

%e The 2nd convergent is 22/7 = 3.142857 142857 ..., whose period is 6, so a(2) = 6.

%e The 3rd convergent is 333/106 = 3.1 4150943396226 4150943396226 ..., whose period is 13, so a(3) = 13.

%o (Sage)

%o st_clenov = 30

%o def A236250(n) :

%o vu = continued_fraction_list(pi, nterms=st_clenov);

%o p = []

%o for i in (0..n) :

%o p.append(convergents(vu)[i].period())

%o return(p)

%o A236250(st_clenov-1);

%Y Cf. A001203, A007732, A084407.

%K nonn,base

%O 1,2

%A _Jani Melik_, Jan 21 2014