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A233454
Numbers k such that k^8 starts with k itself (in base 10).
7
0, 1, 2, 10, 14, 72, 100, 139, 518, 1000, 10000, 13895, 19307, 26827, 37276, 100000, 1000000, 10000000, 13894955, 26826958, 100000000, 193069773, 517947468, 1000000000, 1930697729, 10000000000, 100000000000, 268269579528, 1000000000000, 3727593720315
OFFSET
1,3
EXAMPLE
2^8 = 256 begins with 2, so 2 is in the sequence.
MATHEMATICA
Join[{0}, Select[Range@ 1000000, Take[IntegerDigits[#^8], IntegerLength@ #] == IntegerDigits@ # &]] (* Michael De Vlieger, Aug 31 2015 *)
PROG
(PARI) r=88; print1(1, ", "); e=8; for(n=2, r, p=round((10^(1/(e-1)))^n); f=p^e; b=10^(#Str(f)-#Str(p)); if((f-lift(Mod(f, b)))/b==p, print1(p, ", ")));
KEYWORD
nonn,base,easy
AUTHOR
EXTENSIONS
0 inserted by Juhani Heino, Aug 31 2015
STATUS
approved