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A232099
Numbers n such that {largest m such that 1, 2, ..., m divide n} is different from {largest m such that m! divides n^2}.
6
840, 2520, 4200, 5880, 7560, 9240, 10920, 12600, 14280, 15960, 17640, 19320, 21000, 22680, 24360, 26040, 27720, 29400, 31080, 32760, 34440, 36120, 37800, 39480, 41160, 42840, 44520, 46200, 47880, 49560, 51240, 52920, 54600, 55440, 56280, 57960, 59640, 61320, 63000
OFFSET
1,1
COMMENTS
Numbers n such that A055874(n) differs from A232098(n). (By the definition of the sequence).
This sequence is a subset of A055926. Please see there for a proof. From that follows that A055881(a(n))+1 is always composite (in range n=1..100000, only values 6, 8, 9 and 10 occur).
Also, incidentally, for the first five terms, n=1..5, a(n) = 70*A055926(n), then a(6)=77*A055926(6), and the next time the ratio A232099(n)/A055926(n) is integral is at n=21, where a(n) = 82*A055926(21), at n=41 (a(41) = 79*A055926(41) = 79*840 = 66360), at n=136, a(136) = 80*A055926(136) = 80*2772 = 221760 and at n=1489, where a(1489) = 80*A055926(1489) = 80 * 30492 = 2439360. The ratio seems to converge towards some value a little less than 80. Please see the plot generated by Plot2 in the links section.
LINKS
Wikipedia, Wilson's theorem (Please see especially the section "Composite modulus")
FORMULA
For all n, a(n) = A055926(A232100(n)). [Follows from the definition of A232100, but cannot as such be used to compute the sequence. Use the given Scheme-program instead.]
EXAMPLE
840 (= 3*5*7*8) is in the sequence as all natural numbers up to 8 divide 840, but the largest factorial that divides its square, 705600, is 7! (840^2 = 140 * 5040), and 7 differs from 8.
PROG
(Scheme, with Antti Karttunen's IntSeq-library)
(define A232099 (MATCHING-POS 1 1 (lambda (n) (not (= (A232098 n) (A055874 n))))))
CROSSREFS
Subset of A055926.
Sequence in context: A158402 A361421 A045477 * A005952 A260473 A335141
KEYWORD
nonn
AUTHOR
Antti Karttunen, Nov 18 2013
STATUS
approved