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A230389
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Least k such that n! + k^2 + k is a perfect square.
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1
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0, 0, 1, 5, 3, 119, 719, 260, 180, 495, 3628799, 39916799, 6561647, 9899, 722799, 15308432, 735092, 779904000, 1193692724, 77841862127, 1947879910469375, 7981643124, 231453720692, 37427202522827, 1793894810624, 251579908188224, 286527829489835787, 33866880878997899
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OFFSET
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0,4
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COMMENTS
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a(n) <= n!-1, because with k=n!-1 we have n!+k^2+k = n! + (n!)^2 - 2*n! + 1 + n! - 1 = (n!)^2, a perfect square.
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LINKS
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EXAMPLE
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4! + 3^2+3 = 24+12 = 36, a perfect square, so a(4)=3.
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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