A226215 Zeckendorf distance between n! and (n+1)! .

1, 2, 5, 11, 18, 20, 36, 45, 49, 53, 69, 83, 94, 105, 116, 122, 122, 146, 164, 178, 191, 204, 217, 229, 244, 253, 265, 263, 293, 309, 328, 339, 357, 372, 385, 400, 415, 430, 447, 462, 476, 490, 504, 516, 541, 536, 573, 580, 600, 618, 636, 654, 671, 686, 704

Offset

1,2

Comments

Zeckendorf distance is defined at A226207. For n = 100, the Zeckendorf distance between n! and (n+1)! is 704, compared to the linear distance which exceeds 10^150; in general, the Zeckendorf distance between two large integers tends to be notably less than the ordinary distance.

Links

Clark Kimberling, Table of n, a(n) for n = 1..200

Example

4! = 21 + 3 -> 13 + 2 -> 8 + 1 -> 5 -> 3, and 5! = 89 + 21 + 8 + 2 -> 55 + 13 + 5 + 1 -> 34 + 8 + 3 -> 21 + 5 + 2 -> 13 + 3 + 1 -> 8 + 2 -> 5 + 1 -> 3.   The total number of Zeckendorf downshifts (i.e., arrows) is 4 + 7, so that a(4) = D(24,120) = 11.

Mathematica

zeck[n_Integer] := Block[{k = Ceiling[Log[GoldenRatio, n*Sqrt[5]]], t = n, z = {}},    While[k > 1, If[t >= Fibonacci[k], AppendTo[z, 1]; t = t - Fibonacci[k], AppendTo[z, 0]]; k--]; If[n > 0 && z[[1]] == 0, Rest[z], z]]; d[n1_, n2_] := Module[{z1 = zeck[n1], z2 = zeck[n2]}, Length[z1] + Length[z2] - 2 (NestWhile[# + 1 &, 1, z1[[#]] == z2[[#]] &, 1,
Min[{Length[z1], Length[z2]}]] - 1)]; lst = Map[d[#!, (#+1)!]] &, Range[100]] (* Peter J. C. Moses, May 30 2013 *)

Crossrefs

Cf. A226080, A226207.

Sequence in context: A191053 A209493 A117877 * A169745 A171769 A025200

Adjacent sequences: A226212 A226213 A226214 * A226216 A226217 A226218

Keyword

nonn,easy

Author

Clark Kimberling, May 31 2013

Status

approved