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A226211
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Zeckendorf distance between n and 2n.
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3
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1, 1, 1, 4, 3, 5, 6, 5, 7, 7, 8, 8, 7, 7, 9, 9, 8, 10, 10, 10, 9, 9, 9, 11, 11, 11, 11, 10, 12, 12, 12, 12, 12, 11, 11, 11, 11, 13, 13, 13, 13, 13, 13, 13, 12, 12, 14, 14, 14, 14, 14, 14, 14, 14, 13, 13, 13, 13, 13, 13, 13, 15, 15, 15, 15, 15, 15, 15, 15, 15
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OFFSET
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1,4
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COMMENTS
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Zeckendorf distance is defined at A226207.
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LINKS
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EXAMPLE
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11 = 8 + 3 -> 5 + 2 -> 3 + 1 -> 2, and 22 = 21 + 1 -> 13 -> 8 -> 5 -> 3 -> 2. The total number of Zeckendorf downshifts (i.e., arrows) is 8, so that a(11) = D(11,22) = 8.
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MATHEMATICA
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zeck[n_Integer] := Block[{k = Ceiling[Log[GoldenRatio, n*Sqrt[5]]], t = n, z = {}}, While[k > 1, If[t >= Fibonacci[k], AppendTo[z, 1]; t = t - Fibonacci[k], AppendTo[z, 0]]; k--]; If[n > 0 && z[[1]] == 0, Rest[z], z]]; d[n1_, n2_] := Module[{z1 = zeck[n1], z2 = zeck[n2]}, Length[z1] + Length[z2] - 2 (NestWhile[# + 1 &, 1, z1[[#]] == z2[[#]] &, 1,
Min[{Length[z1], Length[z2]}]] - 1)]; lst = Map[d[#, 2# &, Range[100]] (* Peter J. C. Moses, May 30 2013 *)
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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