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A221644
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Let abcd... be the decimal expansion of k. Sequence lists numbers k such that 1/a + 2/b + 3/c + 4/d + ... is an integer.
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1
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1, 11, 12, 24, 33, 111, 113, 121, 123, 139, 142, 146, 155, 184, 212, 216, 222, 226, 241, 243, 331, 333, 369, 414, 424, 482, 486, 649, 662, 666, 848, 1111, 1112, 1114, 1128, 1131, 1132, 1134, 1168, 1177, 1196, 1211, 1212, 1214, 1228, 1231, 1232, 1234, 1268
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OFFSET
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1,2
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COMMENTS
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The repunits numbers 1, 11, 111, 1111, ... (A002275) are in the sequence.
The first nine terms 1, 12, 123, 1234, ... of A007908 are in the sequence.
If a number of the form ab1 is in the sequence, the corresponding number of the form ab3 is also in the sequence.
If a number of the form abc1 is in the sequence, the corresponding number of the form abc2 is also in the sequence.
If a number of the form abc11 is in the sequence, the corresponding number of the form abc15 is also in the sequence.
The first nine terms 1, 12, 113, 1114, 11115, ... of A198375 are in the sequence.
In the general case, if n = abcd...q is in the sequence where q is the k-th decimal digit of n, the number abcd...qr is also in the sequence if k+1 is divisible by r; for example, 82812 is in the sequence => 828121, 828122, 828123 and 828126 are also in the sequence because 6 is divisible by 1, 2, 3 and 6.
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LINKS
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EXAMPLE
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184 is in the sequence because 1/1 + 2/8 + 3/4 = 2.
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MAPLE
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with(numtheory):for n from 1 to 2000 do: d:=convert(n, base, 10):n1:=nops(d):p:=product('d[i]', 'i'=1..n1):if p<>0 then s:=sum('i/d[n1-i+1] ', 'i'=1..n1):if s=floor(s) then printf(`%d, `, n):else fi:fi:od:
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MATHEMATICA
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Select[Range[1300], FreeQ[IntegerDigits[#], 0]&&IntegerQ[Total[ Range[ IntegerLength[ #]]/ IntegerDigits[ #]]]&] (* Harvey P. Dale, May 16 2018 *)
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PROG
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(PARI) isok(n) = my(d=digits(n)); vecmin(d) && (denominator(sum(k=1, #d, k/d[k])) == 1); \\ Michel Marcus, Sep 14 2017
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CROSSREFS
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KEYWORD
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nonn,base,less
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AUTHOR
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STATUS
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approved
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