OFFSET
0,4
COMMENTS
sech(x) = 1/cosh(x).
The sequence gives only 2n-th derivatives because (2n+1)-th derivatives are 0.
FORMULA
a(n) = (2n)! * [x^(2n)] sech(x)^cosh(x).
MAPLE
a:= n-> (2*n)!* coeff(series(sech(x)^cosh(x), x, 2*n+1), x, 2*n):
seq(a(n), n=0..20); # Alois P. Heinz, Aug 20 2012
MATHEMATICA
f[x_] := Sech[x]^Cosh[x]; Table[Derivative[2*n][f][0], {n, 0, 17}]
CROSSREFS
KEYWORD
sign
AUTHOR
Michel Lagneau, Aug 20 2012
STATUS
approved