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Positions of zeros in A214979.
4

%I #6 Oct 26 2012 16:16:00

%S 1,2,3,5,6,8,9,10,16,17,24,26,27,28,45,46,71,73,74,75,121,122,194,196,

%T 197,198,320,321,516,518,519,520,841,842,1359,1361,1362,1363,2205,

%U 2206,3566,3568,3569,3570,5776,5777,9344,9346,9347,9348,15125

%N Positions of zeros in A214979.

%C Let U(n) and V(n) be the number of terms in the Lucas representations and Zeckendorf (Fibonacci) representations, respectively, of all the numbers 1,2,...,n. Then A214980 is the sequence of zeros of the sequence A214979(n) = V(n) - U(n). It is conjectured at A214979 that A214980 is infinite.

%H Clark Kimberling, <a href="/A214980/b214980.txt">Table of n, a(n) for n = 1..58</a>

%t (See the program at A214979.)

%Y Cf. A214977, A214978, A214979, A214981, A000032, A000045.

%K nonn

%O 1,2

%A _Clark Kimberling_, Oct 22 2012