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%I #91 May 31 2022 11:20:58
%S 3,5,11,29,419,1429,1429,315589,1729001,57762431,1724478911,
%T 6188402219,349152569039,1430083494841,390499187164241,
%U 1010518715554349,18628320726623609,522124211958421799,522124211958421799,5936798290039408015951,311263131154464891496249
%N Least prime p such that the first n primes divide p^2-1.
%C (a(n)^2 - 1) / A002110(n) is congruent to 0 (mod 4). (a(n)^2 - 1) / (4*A002110(n)) = A215085(n). [_J. Stauduhar_, Aug 03 2012]
%C a(n) == +1 or -1 (mod prime(i)) for every i=1,2,...,n. The system of congruences x == +1 or -1 (mod prime(i)), i=1,2,...,n, has 2^(n-1) solutions modulo A002110(n) so that a(n) represents the smallest prime in the corresponding residue classes, allowing efficient computation (see PARI program). - _Max Alekseyev_, Aug 22 2012
%H Max Alekseyev, <a href="/A214089/b214089.txt">Table of n, a(n) for n = 1..32</a>
%e a(5) = 419: 419^2-1 = 175560 = 2^3*3*5*7*11*19 contains the first 5 primes.
%e a(7) = 1429: 1428=2^2*3*7*17, 1430=2*5*11*13 contains the first 7 primes.
%e a(8) = 315589: 315589^2-1 = 2^3*3*5*7*11*13*17^2*19*151 contains the first 8 primes.
%p A214089 := proc(n)
%p local m,k,p;
%p m:= 2*mul(ithprime(j),j=1..n);
%p for k from 1 do
%p p:= sqrt(m*k+1);
%p if type(p,integer) and isprime(p) then return(p)
%p end if
%p end do
%p end proc;
%p # _Robert Israel_, Aug 19 2012
%t f[n_] := Block[{k = 1, p = Times @@ Prime@Range@n}, While[! IntegerQ@Sqrt[4 k*p + 1], k++]; Block[{j = k}, While[! PrimeQ[Sqrt[4 j*p + 1]], j++]; Sqrt[4 j*p + 1]]]; Array[f, 10] (* _J. Stauduhar_, Aug 18 2012 *)
%o (PARI) A214089(n) = {
%o local(a,k=4,p) ;
%o a=prod(j=1,n,prime(j)) ;
%o while(1,
%o if( issquare(k*a+1, &p),
%o if(isprime(p),
%o return(p);
%o ) ;
%o ) ;
%o k+=4;
%o ) ;
%o } ;
%o (PARI) { a(n) = local(B,q); B=prod(i=1,n,prime(i))^2; forvec(v=vector(n-1,i,[0,1]), q=chinese(concat(vector(n-1,i,Mod((-1)^v[i],prime(i+1))),[Mod(1,2)])); forstep(s=lift(q),B-1,q.mod,if(ispseudoprime(s),B=s;break)) ); B } /* _Max Alekseyev_, Aug 22 2012 */
%o (Python)
%o from itertools import product
%o from sympy import sieve, prime, isprime
%o from sympy.ntheory.modular import crt
%o def A214089(n): return 3 if n == 1 else int(min(filter(isprime,(crt(tuple(sieve.primerange(prime(n)+1)), t)[0] for t in product((1,-1),repeat=n))))) # _Chai Wah Wu_, May 31 2022
%Y Cf. A073917, A103783.
%K nonn,hard
%O 1,1
%A _Robin Garcia_, Jul 02 2012
%E a(15)-a(16) from _Donovan Johnson_, Jul 25 2012
%E a(17) from _Charles R Greathouse IV_, Aug 08 2012
%E a(18) from _Charles R Greathouse IV_, Aug 16 2012
%E a(19) from _J. Stauduhar_, Aug 18 2012
%E a(20)-a(32) from _Max Alekseyev_, Aug 22 2012
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