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A213852
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Least m>0 such that n+1+m and n-m are relatively prime.
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1
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2, 1, 1, 2, 1, 1, 3, 1, 1, 2, 1, 1, 2, 1, 1, 2, 1, 1, 2, 1, 1, 3, 1, 1, 2, 1, 1, 2, 1, 1, 2, 1, 1, 2, 1, 1, 3, 1, 1, 2, 1, 1, 2, 1, 1, 2, 1, 1, 2, 1, 1, 5, 1, 1, 2, 1, 1, 2, 1, 1, 2, 1, 1, 2, 1, 1, 3, 1, 1, 2, 1, 1, 2, 1, 1, 2, 1, 1, 2, 1, 1, 3, 1, 1, 2, 1, 1, 2, 1, 1, 2, 1, 1, 2, 1, 1, 3, 1, 1
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OFFSET
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1,1
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COMMENTS
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a(n) > 1 for n == 1 mod 3, a(n) > 2 for n == 7 mod 15, a(n) > 3 for n == 52 mod 105, a(n) > 5 for n == 577 mod 1155, and so on, see A070826. - Ralf Stephan, Mar 16 2014
It appears that we get this sequence if we bisect A071222 and then divide by 2. - N. J. A. Sloane, May 17 2019
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LINKS
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EXAMPLE
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gcd(9,6) = 3, gcd(10,5) = 5, gcd(11,4) = 1, so that a(7) = 3.
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MATHEMATICA
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Table[m = 1; While[GCD[n+1+m, n-m] != 1, m++]; m, {n, 1, 140}]
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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