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A210950
Triangle read by rows: T(n,k) = number of parts in the k-th column of the partitions of n but with the partitions aligned to the right margin.
3
1, 1, 2, 1, 2, 3, 1, 2, 4, 5, 1, 2, 4, 6, 7, 1, 2, 4, 7, 10, 11, 1, 2, 4, 7, 11, 14, 15, 1, 2, 4, 7, 12, 17, 21, 22, 1, 2, 4, 7, 12, 18, 25, 29, 30, 1, 2, 4, 7, 12, 19, 28, 36, 41, 42, 1, 2, 4, 7, 12, 19, 29, 40, 50, 55, 56, 1, 2, 4, 7, 12, 19, 30, 43
OFFSET
1,3
COMMENTS
Index of the first partition of n that has k parts, when the partitions of n are listed in reverse lexicographic order, as in Mathematica's IntegerPartitions[n]. - Clark Kimberling, Oct 16 2023
FORMULA
T(n,k) = Sum_{j=1..n} A210951(j,k).
EXAMPLE
For n = 6 the partitions of 6 aligned to the right margin look like this:
.
. 6
. 3 + 3
. 4 + 2
. 2 + 2 + 2
. 5 + 1
. 3 + 2 + 1
. 4 + 1 + 1
. 2 + 2 + 1 + 1
. 3 + 1 + 1 + 1
. 2 + 1 + 1 + 1 + 1
. 1 + 1 + 1 + 1 + 1 + 1
.
The number of parts in columns 1-6 are
. 1, 2, 4, 7, 10, 11, the same as the 6th row of triangle.
Triangle begins:
1;
1, 2;
1, 2, 3;
1, 2, 4, 5;
1, 2, 4, 6, 7;
1, 2, 4, 7, 10, 11;
1, 2, 4, 7, 11, 14, 15;
1, 2, 4, 7, 12, 17, 21, 22;
1, 2, 4, 7, 12, 18, 25, 29, 30;
1, 2, 4, 7, 12, 19, 28, 36, 41, 42;
1, 2, 4, 7, 12, 19, 29, 40, 50, 55, 56;
1, 2, 4, 7, 12, 19, 30, 43, 58, 70, 76, 77;
MATHEMATICA
m[n_, k_] := Length[IntegerPartitions[n][[k]]]; c[n_] := PartitionsP[n];
t[n_, h_] := Select[Range[c[n]], m[n, #] == h &, 1];
Column[Table[t[n, h], {n, 1, 20}, {h, 1, n}]]
(* Clark Kimberling, Oct 16 2023 *)
CROSSREFS
Mirror of A058399. Row sums give A006128. Right border gives A000041, n >= 1. Rows converge to A000070.
Sequence in context: A116925 A309010 A308500 * A214314 A209435 A263744
KEYWORD
nonn,tabl
AUTHOR
Omar E. Pol, Apr 22 2012
STATUS
approved