%I #8 Feb 13 2023 08:59:31
%S 1,1,3,1,5,9,1,5,21,27,1,5,25,81,81,1,5,25,117,297,243,1,5,25,125,513,
%T 1053,729,1,5,25,125,609,2133,3645,2187,1,5,25,125,625,2853,8505,
%U 12393,6561,1,5,25,125,625,3093,12825,32805,41553,19683,1,5,25,125
%N Triangle of coefficients of polynomials u(n,x) jointly generated with A209998; see the Formula section.
%C Row n starts with 1, 5, 5^2, 5^3,...,5^floor[(n+1)/2] and ends with 3^(n-1).
%C Denoting the general term by T(n,k), we have T(n,n-1)=A081038.
%C Alternating row sums: A000975 (signed).
%C For a discussion and guide to related arrays, see A208510.
%F u(n,x)=x*u(n-1,x)+2x*v(n-1,x)+1,
%F v(n,x)=(x+1)*u(n-1,x)+x*v(n-1,x)+1,
%F where u(1,x)=1, v(1,x)=1.
%e First five rows:
%e 1
%e 1...3
%e 1...5...9
%e 1...5...21...27
%e 1...5...25...81...81
%e First three polynomials u(n,x): 1, 1 + 3x, 1 + 5x + 9x^2.
%t u[1, x_] := 1; v[1, x_] := 1; z = 16;
%t u[n_, x_] := x*u[n - 1, x] + 2 x*v[n - 1, x] + 1;
%t v[n_, x_] := (x + 1)*u[n - 1, x] + 2 x*v[n - 1, x] + 1;
%t Table[Expand[u[n, x]], {n, 1, z/2}]
%t Table[Expand[v[n, x]], {n, 1, z/2}]
%t cu = Table[CoefficientList[u[n, x], x], {n, 1, z}];
%t TableForm[cu]
%t Flatten[%] (* A209996 *)
%t Table[Expand[v[n, x]], {n, 1, z}]
%t cv = Table[CoefficientList[v[n, x], x], {n, 1, z}];
%t TableForm[cv]
%t Flatten[%] (* A209998 *)
%Y Cf. A209998, A208510.
%K nonn,tabl
%O 1,3
%A _Clark Kimberling_, Mar 23 2012